Maths Extension 2 Predictions/Thoughts (1 Viewer)

[Hudz777]

Did u get 5 pi as well

no, didn’t get an answer cause ran out of time, but when I drew it up, it was greater than 4pi

 

[Hudz777]

if you sub u = half theta and then split the resultant integral into 0~pi/2 and pi/2~pi you can dummy variable and get the answer ^^

like I trust your 2024 lookin as s

 

[carrotsss]

if you sub u = 2 theta and then split the resultant integral into 0~pi/2 and pi/2~pi you can dummy variable and get the answer ^^

omg that’s so smart

 

[Hudz777]

kidding x

 

[Aminza21]

yeah bro 8.7 m for 13c iv

 

[Aminza21]

let r(t) in y comp = 0

 

[Sam14113]

did everyone else get 2 theta for that integral

Look it’s hard to keep up with all the messages, sorry if someone’s already responded but use t = 2theta and then consider symmetry of function on x=pi/2

 

[scaryshark09]

if you sub u = 2 theta and then split the resultant integral into 0~pi/2 and pi/2~pi you can dummy variable and get the answer ^^

wait, so is the question right???

 

[OZlachy]

What about the poke ball question? That was hard right? or am i the one who had no clue how to do it.

 

[synthesisFR]

no i got d like z^4

Bro same and then I realised just after I felt soo stupid omg bruhhhh it’s because z4 is the same as z but z2 was the same as z conj
I converted it to z then did it and I forgot they wanted z conj

 

[carrotsss]

wait, so is the question right???

it is

 

[Sam14113]

wait, so is the question right???

Yep

 

[pdawg]

yeah bro 8.7 m for 13c iv

how did you end up with 8.7 from the graph?

 

[Sam14113]

What about the poke ball question? That was hard right? or am i the one who had no clue how to do it.

Which one? The sphere vector one?

Struggled there - only got it after the test

 

[Aminza21]

yall know how on earth to do 15b ii?

 

[Hudz777]

let r(t) in y comp = 0

but how? it was only modelled for upwards… because downwards the equations change

 

[Aminza21]

how did you end up with 8.7 from the graph?

let r(t) in y comp = zero and hence this is equal to zero then you get like 9/4t = 1-e^-4t meaning its where the two graphs intersect... then substitute t = 2.25 into r(t) horizontal component

 

[Aminza21]

but how? it was only modelled for upwards… because downwards the equations change

the r(t) function is for both up and down coz its displacement from origin, not dist covered

 

[carrotsss]

yall know how on earth to do 15b ii?

I just fully expanded the LHS and RHS separately (like LHS=… RHS=…) which then showed that LHS=RHS

 

[synthesisFR]

I’m so pissed with the first part of a 14 I made a dumb mistake and then tried to fix it up but then another dumb mistake and I just couldn’t get the answer it was close tho but I didn’t have time to retry it