B bubb Member Joined Oct 3, 2014 Messages 31 Gender Female HSC 2013 Feb 4, 2015 #1 How do we solve for x when it is in ratio? do we divide? or maybe some further factoring with the 8 and 16? x : 8^(2x-1) = 16^(x+3)
How do we solve for x when it is in ratio? do we divide? or maybe some further factoring with the 8 and 16? x : 8^(2x-1) = 16^(x+3)
Squar3root realest nigga Joined Jun 10, 2012 Messages 4,830 Location ya mum gay Gender Male HSC 2025 Uni Grad 2024 Feb 4, 2015 #2 2^3(2x-1) = 2^4(x+3) equate powers 3(2x-1) = 4(x+3) and solve from there
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,109 Gender Undisclosed HSC N/A Feb 5, 2015 #3 I don't think it is a ratio. "solve for x:" means "solve for x such that". If it was a ratio, it would not be possible to solve exactly. I think √ has interpreted it correctly.
I don't think it is a ratio. "solve for x:" means "solve for x such that". If it was a ratio, it would not be possible to solve exactly. I think √ has interpreted it correctly.
