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General Thoughts: Physics (1 Viewer)

kawaiipotato

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Anyone got q21? The height of the wall? I found grqdient of line and subbed into y = ut +1/2 a_y t^2 where u = 0 and t = gradient. Lol dunno if its correct
 

IamKirby

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It's correct, gradient is sx/ux which gives time, then you can sub it into sy = 1/2at^2


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IamKirby

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Sweet. I was put off by a lot of the marks given - I feel like it was a very generous exam.
I felt like it was pretty easy except for 1 or 2 questions but I made a lot of stupid errors I think because I just found that it look really long so I didn't have time to check.


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kawaiipotato

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It's correct, gradient is sx/ux which gives time, then you can sub it into sy = 1/2at^2


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Ah cool. What was the numerical value? I think i remember it being 4. Something?
 

BillKyriakos

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Didn't you just have to use the Vertical displacement formula? I got 2.5m as well
 

BillKyriakos

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Using the given data or the line of best fit?


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I used the data. More specifically, the horizontal displacement and the velocity to find the time and then subbed that into the vertical displacement formula. Maybe I switched off at that stage but yeah that's what I did
 

IamKirby

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I used the data. More specifically, the horizontal displacement and the velocity to find the time and then subbed that into the vertical displacement formula. Maybe I switched off at that stage but yeah that's what I did
That's right but I think they wanted us to use the gradient of our line of best fit because it's more accurate or something but not sure. Either way I got 2.5 because my line passed through the final point anyway.


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