K
khorne
Guest
correcto something like thisPi ln2 + pi^2/2 - 2pi using radius (1-x) and height f(x) I think
correcto something like thisPi ln2 + pi^2/2 - 2pi using radius (1-x) and height f(x) I think
You found one angle, theta as parallel and since the other angle on the straight line was 180- theta because of the triangle, then the angle sum was 2 theta, thus both angles were theta. EzyAlso guys? The circular motion question worked out perfectly - you needed to use your diagram well. It was definitely theta and not 90-theta.
Sent from my GT-I9100 using Tapatalk
Yepcorrecto something like this
I remember it being small like 1/2 or 1/4? I wasnt sure if it was correct thoughIt wasn't difficult but Q3(b)...anyone remember their answer?
1/2It wasn't difficult but Q3(b)...anyone remember their answer?
i had 2 but am not sureIt wasn't difficult but Q3(b)...anyone remember their answer?
It wasn't difficult but Q3(b)...anyone remember their answer?
I got 1/2 too! *high five*I remember it being small like 1/2 or 1/4? I wasnt sure if it was correct though
i confirm thisPi ln2 + pi^2/2 - 2pi using radius (1-x) and height f(x) I think
yay! at least I got something rightI got 1/2 too! *high five*
Same >.< Wrote it down and was like "lol that can't be right, oh wells".I got a 1/2 too!!
I felt uneasy because the answer looked to simple
for 7a) sorry to be annoying but how did you guys get this part? pi^ (2/2-2pi) lol i doubt anyone will bother answering this haha I'll just go check terry lee when he finishes his solutioncorrecto something like this