Solve z^2 + (1+i)z + 2i = 0, expressing the roots in mod-arg form. If z1, z2 are these roots, prove that |z1| = |z2| = /2 (uh how do you do square root signs..)
, and that arg z1 + arg z2 = pie/2
Well this question is really confusing me.. and seems like I m not getting any where..
please...