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i dont get y R:-pi/2 <= y <= sin^-1 (1\4) isnt it jus -pi/2<=y<=pi/2?

oh yer ill edit now

Question 24. In a flock of 1000 chickens, the number P infected with a disease at time t years is given by P=1000/(1+ce^-1000t) where c is a constant i.Show that eventually, all the chickens will be infected. ii.Suppose that when time t=0, exactly one chicken was infected...

4cos2x=3sec2x 4cos2x=3/cos2x 4cos²2x=3 cos²2x=3/4 cos2x=+-√3/2 2x=π/6, 5π/6, 7π/6, 11π/6, 13π/6, 17π/6, 19π/6 23π/6 x=π/12, 5π/12, 7π//12, 11π/12, 13π/12, 17π/12, 19π/12, 23π/12

x=cos2t - sin2t = √2/√2 (cos2t - sin2t) (multiply top and bottom by √2) = √2 (1/√2 x cos2t - 1/√2 x sin2t) = √2 (cos(pi/4)xcos2t - sin(pi/4)xsin2t) since cos(pi/4)=1/√2 and sin(pi/4)=1/√2 = √2 (cos(2t+pi/4)) using the trig identity cos(a+b)=cosaxcosb-sinaxsinb = √2...

they could ask u inv. trig graphs.

different answer? ill recheck.

You know that this is a temperature question so that it relates to Newton's law of cooling which states that the cooling rate of a body is proportional to the difference between the temperature of a body and that of surrounding medium. i.e dT/dt = -k(T-M) where T is the temperature at...

I hope they dont put problems on maxima/minima in question 7.

A container contains 20 lollies of 3 types (5 black, 5 white and 10 clear). Ben Bob and Peter decides to choose 5 lollies each, Ben would only choose the lollies that has an opposite colour to what peter chooses ( i.e. Ben would only choose white if Peter chooses black and vice versa ) unless...

Please Be Graphs....i Hope Itz Graphing For Atleast 1 Part

7c) Prove that for any positive integer m, [2m+1]/[2m+4] <= sqr.root [(3m-2)/(3m+1)] Hence deduce that (1/2)(5/8)(7/10).....(2n+1/2n+4) <= 1/sqrroot(3n+1) also 8bi) Show that r+1/r-1 = 1 + 2/r + 2/r^2 + 2/r^3 + ..... + 2/r^n + 2/r^(n+1) ii) show that sum of...

GL EVERYONE!!! i hope u all do well.

did u approximate n?.... if 4n+1=1001 n=250 (for the mid inequality) but 4(250)+3 is not equal to 10^-3 (as in the right inequality) ......unless i did something wrong....

ohhh ok.....but then if i let y=0, 0 < 0 - 0/3 +1/5 - ...... + 0/4n+1 < 1/4n+3 did u mean let y=1, since theres a - pi/4 in the middle inequality?

cool thx, any ideas on iii) and iv)

yeh i got that part sorry didnt mention that to u but thx anyway.....u kno how to do parts iii) and iv)?.......even part ii), i can do it but im not sure if im correct.

i have no idea sorry, but i really need help on inequalities.....very weak at it.....i dunno how to approach some of them.

1997 4u maths 6a) The serues 1-x^2+x^4-.....+x^4n has 2n+1 terms i) Explain why 1-x^2+x^4-.....+x^4n = [1+x^(4n+2)]/[1+x^2] ii) Hence show that 1/[1+x^2] <= 1-x^2+x^4-......+x^4n <= 1/[1+x^2] + x^(4n+2) iii) Hence show that, if 0<=y<=1, then inv.tan y <= y - (y^3)/3 +...

i dont have a diagram here but if u do u'd prolly get it, Tcos30 = mg Tsin 30 = mv^2/r (since v=rw, where w = omega) = mrw^2 divide these equations to eliminate T, therefore, tan 30 = rw^2/g now, sin 30 = r/1 = 1/2 so, tan 30 = 1/2 x w^2/9.8 1/sqr...