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*Just by extension, because the reverse reaction is being favoured it means that more of the H_2 O and CuCl_4 2- is consumed in order to obtain a greater yield of Cu(H_2 O)_4 2+ and Cl 1- in this instance. This could possibly mean that the solution of Cu(H_2 O)_4 2+ has colour-altering potential...

To suit the question, when there is an increase of H_2 O in the green solution, the equilibrium is said to shift left (given), meaning it will favour the reverse reaction which decreases the concentration of H_2 O present in solution- resulting in a colour change. Cu(H_2 O)_4 2+ is not pure...