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Thank you for your explanation, yes, that makes sense now. :)

Thanks I understand, (you just simplify again, then multiply each term by x. How's the x can't = 0 on the end impact?

Ah, thanks heaps. That makes sense. And the reason that x can't = 1, is because the bottom of the fraction cannot = 0, am I right. Thanks. :)

How do you get to the last line?? Also how about this q: (I just can't get the last part) The graph of y = \frac{x^2 +15x +14}{x + 1} is the line y= x +14 (I think) with a discontinuity at the point _________?. Thanks. :)

Sorry, getting a bit mixed up trying to use latex!! I can get how you got to the next step... Now...

Sorry changed now. . . So did you multiply each term by x to get to the next step?? Thanks. :)

Hello, Can someone please help me with this question: If g(x) = \frac{x}{x^2 +1} , show that g(\frac{1}{x}) = g(x), x can't = 0 . Thank you very much. Energised