Recent content by parad0xica

If you do MX2, then 2U maths will not be counted towards your ATAR. If you don't do MX2 but you do MX1, then 2U maths will be counted towards your ATAR.

seems right

That's better but it still fails for a text-file containing: Mathematics is fun. Have a nice day, G. Your program produces 7.

My bad. I should have defined what a word means. A word is a string containing no spaces. "Mathematics is fun. Have a nice day, G." contains 8 words

Question: write a program to count the number of words in a text file.

Re: International Baccalaureate Marathon 2016 Looking at the first term only when going from line 5 to line 6, you did this: \cos 2x = 1 - 2 \sin ^2 2x I think it was an issue of focus, not of lack of knowledge

Re: International Baccalaureate Marathon 2016 This: 4 (1-sin^{2}x) sin x (1-2sin^{2}2x)+sin \ x[1-8 sin^{2}x (1-sin^{2}x)] To this: (4-4sin^{2}x)(sinx-2 \times 2 \ sinx cos x \ 2 sin x cos x)+sin x[1-8sin^{2}x+8sin^{4}x] But it should be: (4-4sin^{2}x)(sinx-2 \times \underline{sin x}...

Re: International Baccalaureate Marathon 2016 To the above working out, you can verify the solution by plugging in x = pi/2. RHS yields 20 which exceeds the range of the sine function. So you probably made a small error somewhere pi/2 because sin(pi/2) is easily calculated

C code. Printing is not perfect when (two or more)-digit numbers exists. #include <stdio.h> #include <stdlib.h> //recursive factorial function int factorial (int num){ if (num == 0 || num == 1) { return 1; } return num*factorial(num-1); } void printSpace (int num){ while (--num >=...

Thanks. I don't know why I didn't use that fundamental probability concept in this question even though I used it in Q3

Q4) P(1 machine break down) = 1/45. P(1 machine not break down) = 1 - 1/45 = 44/45. a) P(neither break down) = 44/45 * 44/45. b) P(1 machine break down AND 1 machine no break down(?)) = 1/45 * 44/45.

Q6) Structure of combination is: _ _ _ a) Pick a 9, then pick an 11 P(pick a 9 from first set) = 1/10. P(pick an 11 from second set) = 1/20. Therefore, P("911") = 1/10 * 1/20 = 1/200. b) Cannot pick 10 otherwise we get a number greater than 100. So pick 1 or 2 or ... or 9 then pick 1 or 2...

Q3) a) Probability of winning first prize is 20/5000. Now Mary has 19 non-void tickets and the lottery has 4999 non-void tickets. So probability of winning second prize is 19/4999. Therefore probability of winning first & second prize is 20/5000 * 19/4999 = 19/1249750. b) To win second...

Amount of balls = 9. Q1) a) Pick a yellow ball (3/9), replace, then pick a black ball (2/9). Probability is 3/9 * 2/9 = 2/27. OR pick a black ball first (2/9), replace, then pick a yellow ball (3/9). Probability is 2/27. Add both to get 4/27. b) Yellow first (3/9), do not...

C code: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i, j = 0, n = atoi(argv[1]); while (j < 2) { // printing the "arm" for (i = 0; i < n; i++) { printf("*"); } printf("\n"); // printing the "spine" for (i = 0; i < n/2; i++)...