NSG 2020 questions I got wrong - could someone please walk me through them? (1 Viewer)

[SadCeliac]

From NSG 2020

Questions are attached:

 

[nsw..wollongong]

for question 9, i think the only organic ones would be the propanoic acid and the HCN

 

[SadCeliac]

for question 9, i think the only organic ones would be the propanoic acid and the HCN

but last one is methanoic acid

 

[SadCeliac]

isnt HCN cyanic acid??? which isnt technically organic?? just remembering now

 

[nsw..wollongong]

but last one is methanoic acid

no its hydrogen carbonate

 

[nsw..wollongong]

isnt HCN cyanic acid??? which isnt technically organic?? just remembering now

nah its organic bc of the C-N bond (like if there's a C-O or a C-H bond)

 

[SadCeliac]

no its hydrogen carbonate

im sorry isnt HOOCH just methanoic acid??

 

[SadCeliac]

nah its organic bc of the C-N bond (like if there's a C-O or a C-H bond)

organic or inorganic *

 

[nsw..wollongong]

wait shit ur right the answer should be 3 then

 

[synthesisFR]

im it should be 3 not 2

 

[nsw..wollongong]

organic or inorganic *

HCN = organic

 

[SadCeliac]

im it should be 3 not 2

either way i got it wrong whooo

 

[SadCeliac]

okay what about the other two - the calc one i have no clue how to do and the radiation one i just need some clarification on what filtrate/residue is

 

[synthesisFR]

what do u need for the first one

 

[bigman19191]

Question 8:

Ethanol and methanoic acid will reflux to produce ethyl methanoate (an ester). You should first write out an equation for this

Determine the number of moles of both ethanol and methanoic acid. This can be done by using n = m/MM
n(ethanol) = 3.50g / 46.068 g/mol = 0.07597 mol
n(methanoic acid) = 5.75g / 60.052g/mol = 0.09575 mol
Ethanol is the limiting reagent meaning it gets used up completely.
Therefore, the n(ethyl methanoate) = 0.07597 mol since they are in a 1:1 stoichiometry ratio

Now you can calculate the mass of the product extracted
m(ethyl methanoate) = 0.07597 mol x 74.078 g/mol = 5.63g

However, the mass was found to be 24% of the expected result
So 5.63g x 0.24 = 1.35g

 

[SadCeliac]

Question 9:

Ethanol and methanoic acid will reflux to produce ethyl methanoate (an ester). You should first write out an equation for this

Determine the number of moles of both ethanol and methanoic acid. This can be done by using n = m/MM
n(ethanol) = 3.50g / 46.068 g/mol = 0.07597 mol
n(methanoic acid) = 5.75g / 60.052g/mol = 0.09575 mol
Ethanol is the limiting reagent meaning it gets used up completely.
Therefore, the n(ethyl methanoate) = 0.07597 mol since they are in a 1:1 stoichiometry ratio

Now you can calculate the mass of the product extracted
m(ethyl methanoate) = 0.07597 mol x 74.078 g/mol = 5.63g

However, the mass was found to be 24% of the expected result
So 5.63g x 0.24 = 1.35g

lifesaver tysm

 

[SadCeliac]

I also have this question from later in the paper - no clue how to do it:



I estimated equivalence point at 8.2 ish but NO CLUE WHAT TO DO FOR C!!!

please help <3

 

[nsw..wollongong]

wait wait WAITTT I GOT IT

 

[bigman19191]

Question 9:

The two organic compounds are CH3CH2COOH (propanoic acid) and HOOCH (methanoic acid). They both contain a carboxyl functional group which is organic due to the presence of carbon. As such, the answer cannot the HCl nor H2SO4. HCN is not organic acid because there is no -COOH group.

 

[SadCeliac]

Question 10:

The two organic compounds are CH3CH2COOH (propanoic acid) and HOOCH (methanoic acid). They both contain a carboxyl functional group which is organic due to the presence of carbon. As such, the answer cannot the HCl nor H2SO4. HCN is not organic acid because there is no -COOH group.

OH WAS IT ASKING FOR ORGANIC ACID???!?!?!