Matrices help please! (1 Viewer)

mattsteel87

New Member
Joined
Mar 1, 2015
Messages
1
Gender
Undisclosed
HSC
N/A
Can anyone explain the following questions please:

1) For what value of k does the system of equations shown have no solution. (Use a matrix approach to the problem)

x + ky = 1
kx + y = 1


2) For which values of c does the system of equations shown have a solution? (This is best done using a matrix approach and you can use the internet to find the inverse of the 3 x 3 matrix to save some work if you want)

x - y - 3z = 3
2x . + z = 0
2y +7z = c



3) .
27023


Thanks!
 
Last edited:

blyatman

Well-Known Member
Joined
Oct 11, 2018
Messages
539
Gender
Undisclosed
HSC
N/A
You should be able to solve it by using the fact that a linear system is consistent (i.e. has solutions) if and only if the coefficient matrix and augmented matrix have the same rank. The rank of a matrix is simply the number of non-zero rows in its row echelon form.
 

realcareerchats

New Member
Joined
Nov 5, 2022
Messages
8
Gender
Male
HSC
2002
For no solutions the determinant has to be zero...which is ad-bc in the matrix of coefficients...so solve 1-k^2=0 to find values of K such that there are no solutions
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top