can you do this: \frac{1}{n}\sum _{k=1}^{\:n}\:\lim _{n\to \infty }\left(\frac{1}{1+\frac{k^2}{n^2}}\right) then \frac{1}{n}\cdot\sum_{k=1}^{n}1 which equals \frac{1}{n}?\ I'm generally not sure how to solve lim questions involving sums... please help! Thank you! *ps also noticed that latex on BOS is much cleaner - shoutout to whoever cleaned that up :)