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Belle

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Originally posted by ND
If you drew a line through (0, 0) and (.6, 1.85), then you drew a line with gradient t.
I know, but Inhuman was right, I was talking about the first bit with the velocity :p I went the complicated way and didn't think of the simple way and didn't even end up with the right answer. :(

Oh well. My graph will be wrong but maybe I can get a mark for the pretty scale I drew or something... or drawing a straight line...?
 

Squirrel

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my stupid graph had a negative gradient.

i knew it was wrong but i did it anyway.

:(
 

Constip8edSkunk

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u miss read the question, it says graph it when the velocity is varied...

even by assuming velocity is constant, u can never get a graph because the range would be constant too, unless you have a adjustable table :D
 

walla

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The time taken is constant (unaffected by horizontal velocity).

x= ut

so the range is directly proportional to horizontal velocity - straight line graph.
 

Sprach

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so the graph looked like this?

| .
| .
| .
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|._________
lol join the dots :D
is that what it looked like? a straight line graph?
 

jims

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not sure, but i used dx = u(x)t so as u(x) increases, dx increases linearly.
 

+Po1ntDeXt3r+

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yer its straight...mine was m=sqrt(2/g) i think it may have been m=sqrt(g/2)
i stuffed it up TWICE
and my points was (0,0) and (1.85,0.6) cos i thought the range was dependent on the velocity. was i wrong?
 

Amish

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I had a good 10mins at the end to think solidly about this question...

I came to the conclsion that it was a linear graph that went through the point (1.85, 0.6). As they asked to show at different velocities my horizontal axis was say....horizontal velocity and vertical was range. I used 6 x values being 1,1.85, 2, 3, 4, 5 and then connected them using straight line so it was pretty much a linear graph with equation y = (12/37)x

Hopefully i got it right :D
 

iH

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it was a straight line.

as velocity increases so does range.

t is constant because it is a variable affected only by gravity. assuming gravity and the table height are the same, t stays the same.

one straight line y = x

goes through the origin :)

and if you were smart you also plotted the point correctly as (0.6, 1.875) <--- not sure if that's the exact number (the y value) cos it was hours ago
 

marky

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my friends said it was jst a straight line since bvelocity in the y direction is constant????
 

iH

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.





you might get a mark but with all the wholistic marking. who knows...it kinda shows that u weren't exactly sure what u were talking about....cos the entire thing is determined to figure out if u know that s = vt....and if u knew that you'd see that when v = 0, so is s

Sam
 

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