Advanced math year 11 - simultaneous equations (1 Viewer)

[HazzRat]

(y/4) - (x/3) = 1
(x/2) + (y/5) =10

find x and y

For some reason I can't solve this one. I've tried elimination and substitution but I get the wrong answers each time.

 

[Masaken]

i did it pretty quickly so it might be wrong, but is the answer x = 12, and y = 20?
if so, for the first equation i multiplied each side by 12, so i got 3y-4x=12, and then multiplied each side on the second equation by 10, so i got 2y + 5x = 100. multiply 3y-4x=12 by 5 and 2y+5x=60 by 4, then add --> you should get 23y = 460 --> y = 20, then solve for x

 

[HazzRat]

i did it pretty quickly so it might be wrong, but is the answer x = 12, and y = 20?
if so, for the first equation i multiplied each side by 12, so i got 3y-4x=12, and then multiplied each side on the second equation by 10, so i got 2y + 5x = 100. multiply 3y-4x=12 by 5 and 2y+5x=60 by 4, then add --> you should get 23y = 460 --> y = 20, then solve for x

That is correct. I will doing the elimination method wrong and I made a silly mistake when substituting. I got the right answer eventually.